Remain in same page even after submitting jsp form [duplicate]

Answer 1

You can invoke ajax in your jsp like this:

function test(tg1){
  context = '${pageContext.request.contextPath}';
  var http_request = getXMLHttpRequest();
            if (!http_request) {
        alert('Giving up :( Cannot create an XMLHTTP instance');
        return false;
    }

    http_request.open("POST", context + "/ServletName?tgt1=" + tg1, true);
    http_request.onreadystatechange = function() {
        if (http_request.readyState == 4) {
            if (http_request.status == 200) {
                var response = http_request.responseText;
                //do something if you have a response from the servlet
            }
        }
    };
    http_request.send(null);
}

In your servlet, remove your redirect code.

ResultSet rs=null;  
String Add=request.getParameter("tgt1");  
String user=(String) session.getAttribute("myusername");  
Class.forName("oracle.jdbc.driver.OracleDriver").newInstance();Date d1 = new Date();    
String d1_str = new SimpleDateFormat("yyyy-MM-dd").format(d1);   
Connection con = DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:XE","system","tiger");  
PreparedStatement ps=con.prepareStatement("UPDATE SCOPE1 SET ALLOCATED='"+d1_str+"', SPECIALIST='"+user+"' WHERE DBID='"+Add+"'");  
con.setAutoCommit(true);  
int i=ps.executeUpdate();  

You can add a response from the servlet using response.getWriter().write("something");

Answer 2

As I mentioned in my comment, consider javascript asynchronous calls (AJAX) to your servlet.

In this case your page won't change and you can do all your interaction with the server in the background.

Here is AJAX tutorial

If you are not experienced Javascript programmer, then consider this JavaScript tutorial

JSP on its nature is a servlet, i.e it is server side code, but you can embed javascript to your JSP page, that will work on the client's browser (client side), and send/receive data packets to the server in the background, without submitting the whole page to the server.

Here is the example of JSP and AJAX combination

Answer 3

In your code I can see (parts of) 2 JavaScript functions move() and invoke(but).
The first one moves data from one DOM element ('Allocation') to another ('tgt1'). The second is attempting to submit data to the server/jsp page.

Is that correct and that what you are trying to do?

BTW: you should call them in the order of move(); invoke(...);, NOT other way around because once the form is submitted move() will not run - nothing can happen on the client side, because the processing left the page.

I noticed that in your move() function you disable DOM element "Send" (document.getElementById("Send").disabled=true;) which happens to be your submit button. This action will prevent the form from being submitted, so you should probably remove that line.