I have string of date from xml file of such kind: \'2010-09-09T22:33:44.OZ\'
I need to extract only date and time. I want to ignore symbol T and .OZ (time zone). Whi
select TO_DATE('2010-09-09T22:33:44.OZ'
,'YYYY-MM-DD"T"HH24:MI:SS".OZ"')
from dual;
9/09/2010 10:33:44 PM
If the timezone information is needed:
select to_timestamp_tz('2010-09-09T22:33:44.GMT','YYYY-MM-DD"T"HH24:MI:SS.TZR')
from dual;
09-SEP-10 22.33.44.000000000 GMT
But OZ
isn't a recognised timezone abbreviation, so you'd need to do some pre-conversion of that to something that is.
If you want to just ignore that part, and it's fixed, you can do what @Jeffrey Kemp said:
select to_date('2010-09-09T22:33:44.OZ','YYYY-MM-DD"T"HH24:MI:SS."OZ"')
from dual;
09/09/2010 22:33:44 -- assuming your NLS_DATE_FORMAT is DD/MM/YYYY HH24:MI:SS
If you want to ignore it but it isn't fixed then you'll need to trim it off first, something like (using a bind variable here for brevity):
var input varchar2(32);
exec :input := '2010-09-09T22:33:44.OZ';
select to_date(substr(:input,1,instr(:input,'.') - 1),'YYYY-MM-DD"T"HH24:MI:SS')
from dual;
09/09/2010 22:33:44