Why does new Number(2) != new String(“2”) in JavaScript

Question

The following evaluate to true:

new Number(2) == 2
new String(\"2\") == \"2\"

Obviously, but so do the following:

Answer 1

What I think == is basically does value comparision.

In above all situations it's comparing just values. But in this one

new Number(2) == new String("2")

Both are objects so it doesn't compare values, it tries to compare values of object references. That's why it returns false.

Answer 2

Just try:

new Number(2) == new Number(2)

that returns

false

and you will have the answer: there are 2 different objects that have 2 different references.

Answer 3

Because JavaScript has both primitive and object versions of numbers and strings (and booleans). new Number and new String create object versions, and when you use == with object references, you're comparing object references, not values.

new String(x) and String(x) are fundamentally different things (and that's true with Number as well). With the new operator, you're creating an object. Without the new operator, you're doing type coercion — e.g. String(2) gives you "2" and Number("2") gives you 2.