This question is similar to my last question. Except this time I\'m using letters rather than 6 digit integers. I want to find the out of sequence \"letters\".
Let\
You can convert the char(1) to its ascii number using
ASCII(Letter)
You can then increment this by one and return it to a letter using CHAR (if necessary), so your code would be this:
SELECT * from TABLE1 t1
LEFT OUTER JOIN TABLE2 t2
ON ASCII(t1.INTCol) - 1 = ASCII(t2.INTCol)
AND t1.date = t2.date
WHERE t2.id IS NULL
You can use the ASCII() function to convert a character to its ASCII value:
ASCII(Letter)