Using aria-label to locate and click an element with Python3 and Selenium

Question

I want to click or more respectively, expand the \"Any time\" button. I\'ve tried to locate the element by class_name and xpath. The problem is that the class and xpath are

Answer 1

So, I was just wrestling with this for the last couple days, and it was proving to be a huge headache. The aria-label was basically the only reliable attribute, and the xpath solution was not working for me.

On a whim, I tried using:

driver.find_elements_by_css_selector("[aria-label=XXXX]")

where XXXX was the aria labels that I was searching for. Worked like a charm.

All this to say, try using the css selector. It just works.

Answer 2

Using the aria-label property you can try the following xpath:

driver.find_element_by_xpath("//div[@aria-label='Any time']/div[@class='mn-hd-txt' and text()='Any time']");

OR

driver.find_element_by_xpath("//div[@aria-label='Any time']/div[@class='mn-hd-txt'][text()='Any time']");

If using aria-label property is not a mandatory requirement you can use the following:

driver.find_element_by_xpath("//div[@class='hdtb-mn-hd']/div[@class='mn-hd-txt' and text()='Any time']");

OR

driver.find_element_by_xpath("//div[@class='hdtb-mn-hd']/div[@class='mn-hd-txt'][text()='Any time']");