How to convert int array to int?

Question

What I would like to learn how to do is to convert an int array to an int in C#.

However I want to append the int with the values from the array.

Example:

Answer 1

In C# 3.0 and up:

array.Select((t, i) => t * Convert.ToInt32(Math.Pow(10, array.Length - i - 1))).Sum();

Answer 2

Another simple way:

int[] array =  {5, 6, 2, 4};
int num;
if (Int32.TryParse(string.Join("", array), out num))
{
    //success - handle the number
}
else
{
    //failed - too many digits in the array
}

Trick here is making the array a string of digits then parsing it as integer.

Answer 3

int output = array
    .Select((t, i) => t * Convert.ToInt32(Math.Pow(10, array.Length - i - 1)))
    .Sum();

Answer 4

you can use string stream (include "sstream")

using namespace std; int main(){

int arr[3]={3,2,4};     //your array..

stringstream ss;

ss<<arr[0];   //this can be run as a loop
ss<<arr[1];
ss<<arr[2];


int x;
ss>>x;

cout<<x;        //simply the int arr[3] will be converted to int x..

Answer 5

This would be easy, if you have understood how the decimal system works.

So let me explain that for you: A decimal digit contains single digits by base ten.

This means you have to iterate through this array (backwards!) and multiply by 10^

For an example 5624 means: (5*10^3) + (6*10^2) + (2*10^1) + (4*10^0)

Please consider also: http://en.wikipedia.org/wiki/Horner_scheme

Answer 6

simply multiply each number with 10^ his place in the array.

int[] array = { 5, 6, 2, 4 };
int finalScore = 0;
for (int i = 0; i < array.Length; i++)
{
    finalScore += array[i] * Convert.ToInt32(Math.Pow(10, array.Length-i-1));
}