how do I increment an integer variable I passed into a function in Scala?

Question

I declared a variable outside the function like this:

var s: Int = 0

passed it such as this:

def function(s: Int):         


        

Answer 1

If you just want to increment a variable starting with 3

val nextId = { var i = 3; () => { i += 1; i } }

then invoke it:

nextId()

Answer 2

I have also just started using Scala this was my work around.

var s: Int = 0

---

def function(s: Int): Boolean={

   var newS = s
   newS = newS + 1 
   s = newS
   return true

}

From What i read you are not passing the same "s" into your function as is in the rest of the code. I am sure there is a even better way but this is working for me.

Answer 3

If you just want continuously increasing integers, you can use a Stream.

val numberStream = Stream.iterate(0)(_ + 1).iterator

That creates an iterator over a never-ending stream of number, starting at zero. Then, to get the next number, call

val number: Int = numberStream.next

Answer 4

First of all, I will repeat my words of caution: solution below is both obscure and inefficient, if it possible try to stick with values.

implicit class MutableInt(var value: Int) {
  def inc() = { value+=1 } 
}

def function(s: MutableInt): Boolean={
   s.inc() // parentheses here to denote that method has side effects
   return true
}

And here is code in action:

scala> val x: MutableInt = 0 
x: MutableInt = MutableInt@44e70ff

scala> function(x)
res0: Boolean = true

scala> x.value
res1: Int = 1

Answer 5

You don't.

A var is a name that refers to a reference which might be changed. When you call a function, you pass the reference itself, and a new name gets bound to it.

So, to change what reference the name points to, you need a reference to whatever contains the name. If it is an object, that's easy enough. If it is a local variable, then it is not possible.

See also call by reference, though I don't think this question is a true duplicate.