SQL select MAX(COUNT)

Question

I\'m trying to select the user who has the MAX microposts count:

SELECT \"name\", count(*) FROM \"users\" 
  INNER JOIN \"microposts\" ON \"microposts\".\"us         


        

Answer 1

SELECT x.name, MAX(x.count)
FROM (
 SELECT "name", count(*)
  FROM "users" INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id"
  GROUP BY users.id
) x

Answer 2

I'd try with a ORDER BY max DESC LIMIT 1, where maximum is the count(*) field. Something like:

SELECT "name", count(*) maximum FROM "users" 
   INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id 
ORDER BY maximum DESC 
LIMIT 1

I dont' have mysql available now, so I'm doing this on the paper (and it might not work), but it's just an orientation.

Answer 3

It's pretty simple, you can try:

SELECT "name", MAX(count_num) FROM 
(SELECT "name", count(*) as count_num
FROM "users" INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id"
GROUP BY users.id) x

Answer 4

SELECT TOP 1 "name", count(*) AS ItemCount FROM "users" 
INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id
ORDER BY ItemCount DESC

Answer 5

maybe like this:

SELECT "name", count(*) 
FROM "users" 
INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id
HAVING COUNT(microposts) = (SELECT COUNT(microposts) 
                         FROM   users
                         GROUP  BY microposts
                         ORDER  BY COUNT(microposts) DESC 
                         LIMIT  1) 

Didn't test it, but it might work