Why do these two code samples produce different outputs?

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离开以前
离开以前 2021-01-18 02:57

Sample 1:

 class Animal {
     public static void saySomething() { System.out.print(\" Gurrr!\"); 
   }
 }
 class Cow extends Animal {
    public static void         


        
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5条回答
  • 2021-01-18 03:04

    Static methods are tied to the "Class", not the "Instance" of the object. Since you are referring to an "Animal" and calling the static method saySomething(). It will always make the call to "Animal" unless you are referring to a Cow.

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  • 2021-01-18 03:11

    When you call saySomething() on an animal, the actual type of the animal doesn't count because saySomething() is static.

    Animal cow = new Cow();
    cow.saySomething(); 
    

    is the same as

    Animal.saySomething();
    

    A JLS example :

    When a target reference is computed and then discarded because the invocation mode is static, the reference is not examined to see whether it is null:

    class Test {
      static void mountain() {
          System.out.println("Monadnock");
      }
      static Test favorite(){
           System.out.print("Mount ");
           return null;
       }
       public static void main(String[] args) {
           favorite().mountain();
       }
    

    }

    which prints:
    Mount Monadnock
    Here favorite returns null, yet no NullPointerException is thrown.


    Resources :

    • JLS - Is the Chosen Method Appropriate?

    On the same topic :

    • Java Static confusion
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  • 2021-01-18 03:18

    Some of the known Overriding "PITFALLS"

    • static methods cannot be overridden
    • private methods cannot be overridden

    This explains the output.

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  • 2021-01-18 03:22

    You cannot override static methods with the same signature in subclasses, just hide them.

    For class methods, the runtime system invokes the method defined in the compile-time type of the reference on which the method is called. For instance methods, the runtime system invokes the method defined in the runtime type of the reference on which the method is called.

    http://life.csu.edu.au/java-tut/java/javaOO/override.html

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  • 2021-01-18 03:24

    static methods are bound to their class at compile time and cannot be used polymorphically. When you declare a "static" method on Animal, it is forever bound to the Animal class and cannot be overridden. Static methods are bound to the Class object, not an instance of the Class.

    Regular methods are bound at runtime and so the JVM can look at your call to "saySomething" and attempt to determine if you're passing around a subclass of Animal and if so, has it overridden the saySomething() method. Regular methods are bound to an instance of an object, not to the Class itself.

    This is also why you could never do this:

    class Animal
    {
       public abstract static void saySomething();
    }
    

    Since "static" means "bound at compile time", it never makes sense for something to be static and abstract.

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