While trying to create an Ltac definition that loops over a variable-length argument list, I encountered the following unexpected behavior on Coq 8.4pl2. Can anyone explain
Let's expand the last invocation of ltac_loop
to see what's happening:
ltac_loop 1 1 0
-> (fun Y => idtac "hello"; ltac_loop Y) 1 0
-> (idtac "hello"; ltac_loop 1) 0
There you can see the problem: you are trying to apply something that is not a function to an argument, which results in the error you saw. The solution is to rewrite the tactic in continuation-passing style:
Ltac ltac_loop_aux k X :=
match X with
| 0 => k
| _ => (fun Y => ltac_loop_aux ltac:(idtac "hello"; k) Y)
end.
Ltac ltac_loop X := ltac_loop_aux ltac:(idtac "done") X.