I\'m trying to access a member structs variables, but I can\'t seem to get the syntax right. The two compile errors pr. access are: error C2274: \'function-style cast\' : i
You only define a struct there, not allocate one. Try this:
class Foo{
public:
struct Bar{
int otherdata;
} mybar;
int somedata;
};
int main(){
Foo foo;
foo.mybar.otherdata = 5;
cout << foo.mybar.otherdata;
return 0;
}
If you want to reuse the struct in other classes, you can also define the struct outside:
struct Bar {
int otherdata;
};
class Foo {
public:
Bar mybar;
int somedata;
}
You are only declaring Foo::Bar but you don't instantiate it (not sure if that's the correct terminology)
See here for usage:
#include <iostream>
using namespace std;
class Foo
{
public:
struct Bar
{
int otherdata;
};
Bar bar;
int somedata;
};
int main(){
Foo::Bar bar;
bar.otherdata = 6;
cout << bar.otherdata << endl;
Foo foo;
//foo.Bar.otherdata = 5;
foo.bar.otherdata = 5;
//cout << foo.Bar.otherdata;
cout << foo.bar.otherdata << endl;
return 0;
}
Bar
is inner structure defined inside Foo
. Creation of Foo
object does not implicitly create the Bar
's members. You need to explicitly create the object of Bar using Foo::Bar
syntax.
Foo foo;
Foo::Bar fooBar;
fooBar.otherdata = 5;
cout << fooBar.otherdata;
Otherwise,
Create the Bar instance as member in Foo
class.
class Foo{
public:
struct Bar{
int otherdata;
};
int somedata;
Bar myBar; //Now, Foo has Bar's instance as member
};
Foo foo;
foo.myBar.otherdata = 5;
struct Bar{
int otherdata;
};
Here you have just defined a structure but not created any object of it. Hence when you say foo.Bar.otherdata = 5;
it is compiler error. Create a object of struct Bar like Bar m_bar;
and then use Foo.m_bar.otherdata = 5;
You create a nested structure, but you never create any instances of it within the class. You need to say something like:
class Foo{
public:
struct Bar{
int otherdata;
};
Bar bar;
int somedata;
};
You can then say:
foo.bar.otherdata = 5;