Say I have a crontab which runs every 20
minutes and I have a hour range which can vary so lets say a-b
, which in one example could look like
GK27's answer does not fully answer the question, so let me clarify:
cron
will run jobs when the time matches the expression provided. Your expression tells it to run when the minute is divisible by 20 (*/20
) and your hour range tells it to run when the hour is within the specified range inclusively (5-23
). The remaining three *
tell it to match any day, month, and any day of the week.
Therefore the first job will run at 05:00 because the hour, 05
, is in the range 5 to 23 and the minute, 00
, is divisible by 20. The last job will run at 23:40 because the hour, 23
, is in the range 5 to 23 and the minute, 40
, is divisible by 20. It will not run at 00:00 because the hour, 00
, is not in the range 5 to 23.
Yes offcourse it will execute on every 2o mins from 5am till 23 hrs,
* 20 – 20th Minute (Top of the hour)
* 5-23 – 5.20 am,5.40 am,6 am,....23 pm
* * – Every day
* * – Every month
* * - EvryDay of the Week
Documentation for Reference
@Alex's answer is correct, however it took me a while to find a source.
The answer is in man crontab.5
(or also info crontab
) on Debian, Mac OS X, FreeBSD (and other Posix systems):
Ranges of numbers are allowed. Ranges are two numbers separated with a hyphen. The specified range is inclusive. For example, 8-11 for an ``hours'' entry specifies execution at hours 8, 9, 10 and 11.
For my application I wanted a script to run every 5 minutes during business hours (9am - 5pm) and another to run every 5 minutes outside of that. Unfortunately the ranges can't wrap across midnight, so you need to specify 3 ranges (morning, business hours, evening)
*/5 0-8,17-23 * * * outside-hours.sh
*/5 9-16 * * * business-hours.sh
This should run
outside-hours.sh first at 00:00 and finally at 08:55
business-hours.sh first at 09:00 and finally at 16:55
outside-hours.sh first at 17:00 and finally at 23:55