Can I force std::vector to not deallocate its memory after the vector goes out of scope?
For example, if I have
No.
And you're doing it wrong. Return the vector instead so the lifetime works out:
Write your own special Python memory vector class
, something like (most crudely):
template <typename T>
class python_vector
{
T* buffer_;
public:
python_vector(size_t n, const T& value) : buffer_{new T(n)}
{}
// copy, assignment, operator[](), *etc*
~python_vector()
{
// DO NOTHING!
}
}
python_vector<int> foo() {
python_vector<int> v(10,1);
// process v
return v;
}
int main()
{
python_vector<int> bar = foo(); // copy allusion will build only one python_vector here
std::cout << bar[5] << std::endl;
}