How do I convert EVENT_DATE_B - EVENT_DATE_A
which is a number of days to string with HH:MM
format?
If dates are differ only in time part you can use interval day to second. For instance:
SQL> select (to_date('25.12.12 15:37:32', 'DD.MM.YY HH24:MI:SS')
2 - to_date('25.12.12 12:45:45', 'DD.MM.YY HH24:MI:SS')) day(0) to second(0) as Time
3 from dual
4 ;
TIME
-------------
+0 02:51:47
But obviously it will not always be the case. So you could write a long query to calculate different parts of time, but I think I would go with this simple function:
SQL> create or replace function DaysToTime(p_val in number)
2 return varchar2
3 is
4 l_hours number;
5 l_minutes number;
6 l_seconds number;
7 begin
8 l_Hours := 24 * p_val;
9 l_minutes := (l_hours - trunc(l_hours)) * 60;
10 l_seconds := (l_minutes - trunc(l_minutes)) * 60;
11 return to_char(trunc(l_hours), 'fm09') ||':'||
12 to_char(trunc(l_minutes), 'fm09')||':'||
13 to_char(trunc(l_seconds), 'fm09');
14 end;
15 /
Function created
And now the query would be:
SQL> select DaysToTime(to_date('25.12.12 15:37:32', 'DD.MM.YY HH24:MI:SS')
2 - to_date('25.12.12 12:45:45', 'DD.MM.YY HH24:MI:SS')) as Time
3 from dual
4 ;
TIME
----------
02:51:47
Another approach (one query can be on different days):
with tt as (
select numToDsinterval((EVENT_DATE_B - EVENT_DATE_A ), 'DAY') dsint
from t)
select (extract(day from dsint)*24)+extract(hour from dsint) ||
':' ||extract(minute from dsint)
from tt
Here is a sqlfiddle demo
I think you need to find out the number of days between date1 and date2, then subtract this difference from date2 and convert final date to your format. Copy/paste and see the output:
Select date2, days_between, to_char(date2-days_between, 'mm-dd-yyyy hh24:mi:ss') end_date
From
(
Select sysdate date2
, trunc(sysdate)-to_date('20-DEC-2012') days_between --'20-DEC' is start_date
From dual
)
/
select 24 * (EVENT_DATE_B - EVENT_DATE_A) || ':' || '00'
from your_table
SQLFiddle demo