I have an application that has a guid variable which needs to be unique (of course). I know that statistically any guid should just be assumed to be unique, but due to dev/t
You can get the byte components of the guid, so you can just work on that:
static class GuidExtensions
{
private static readonly int[] _guidByteOrder =
new[] { 15, 14, 13, 12, 11, 10, 9, 8, 6, 7, 4, 5, 0, 1, 2, 3 };
public static Guid Increment(this Guid guid)
{
var bytes = guid.ToByteArray();
bool carry = true;
for (int i = 0; i < _guidByteOrder.Length && carry; i++)
{
int index = _guidByteOrder[i];
byte oldValue = bytes[index]++;
carry = oldValue > bytes[index];
}
return new Guid(bytes);
}
}
EDIT: now with correct byte order
Thanks to Thomas Levesque's byte order, here's a nifty LINQ implementation:
static int[] byteOrder = { 15, 14, 13, 12, 11, 10, 9, 8, 6, 7, 4, 5, 0, 1, 2, 3 };
static Guid NextGuid(Guid guid)
{
var bytes = guid.ToByteArray();
var canIncrement = byteOrder.Any(i => ++bytes[i] != 0);
return new Guid(canIncrement ? bytes : new byte[16]);
}
Note it wraps around to Guid.Empty
if you manage to increment it that far.
It would be more efficient if you were to keep incrementing a single copy of bytes
rather than calling ToByteArray
on each GUID in turn.
Verified Solution for Ordered Strings:
private static Guid Increment(Guid guid)
{
byte[] bytes = guid.ToByteArray();
byte[] order = { 15, 14, 13, 12, 11, 10, 9, 8, 6, 7, 4, 5, 0, 1, 2, 3 };
for (int i = 0; i < 16; i++)
{
if (bytes[order[i]] == byte.MaxValue)
{
bytes[order[i]] = 0;
}
else
{
bytes[order[i]]++;
return new Guid(bytes);
}
}
throw new OverflowException("Congratulations you are one in a billion billion billion billion etc...");
}
Verification:
private static Guid IncrementProof(Guid guid, int start, int end)
{
byte[] bytes = guid.ToByteArray();
byte[] order = { 15, 14, 13, 12, 11, 10, 9, 8, 6, 7, 4, 5, 0, 1, 2, 3 };
for (int i = start; i < end; i++)
{
if (bytes[order[i]] == byte.MaxValue)
{
bytes[order[i]] = 0;
}
else
{
bytes[order[i]]++;
return new Guid(bytes);
}
}
throw new OverflowException("Congratulations you are one in a billion billion billion billion etc...");
}
static void Main(string[] args)
{
Guid temp = new Guid();
for (int j = 0; j < 16; j++)
{
for (int i = 0; i < 255; i++)
{
Console.WriteLine(temp.ToString());
temp = IncrementProof(temp, j, j + 1);
}
}
}
Possible solution -- I think this works (not really tested), but want a better solution.
public static Guid Increment(this Guid value)
{
var bytes = value.ToByteArray();
// Note that the order of bytes in the returned byte array is different from the string representation of a Guid value.
// Guid: 00112233-4455-6677-8899-aabbccddeeff
// byte array: 33 22 11 00 55 44 77 66 88 99 AA BB CC DD EE FF
// So the byte order of the following indexes indicates the true low-to-high sequence
if (++bytes[15] == 0) if (++bytes[14] == 0) if (++bytes[13] == 0) if (++bytes[12] == 0) if (++bytes[11] == 0) if (++bytes[10] == 0) // normal order
if (++bytes[9] == 0) if (++bytes[8] == 0) // normal order
if (++bytes[6] == 0) if (++bytes[7] == 0) // reverse order
if (++bytes[5] == 0) if (++bytes[4] == 0) // reverse order
if (++bytes[3] == 0) if (++bytes[2] == 0) if (++bytes[1] == 0) { ++bytes[0]; } // reverse order
return new Guid(bytes);
}
Edit: here is the code I ended up using; props to the answers above for the general technique, although without the "unchecked" clause they both would throw exceptions in some cases. But I also tried to make the below as readable as possible.
private static int[] _guidByteOrder = { 15, 14, 13, 12, 11, 10, 9, 8, 6, 7, 4, 5, 0, 1, 2, 3 };
public static Guid NextGuid(this Guid guid)
{
var bytes = guid.ToByteArray();
for (int i = 0; i < 16; i++)
{
var iByte = _guidByteOrder[i];
unchecked { bytes[iByte] += 1; }
if (bytes[iByte] != 0)
return new Guid(bytes);
}
return Guid.Empty;
}