WPF: Window stays minimized even when setting WindowState explicitly

Question

My application has a tray icon which, when double-clicked, hides or shows the application window. My issue is that I can\'t seem to bring the window to the foreground if it

Answer 1

I cross posted my question on the MSDN Forums and it got answered there. To quote the answer:

---

Some properties on Window that are more like methods, in the sense they cause complex actions to happen, need to happen after the previous action has already completed. One way to get that to happen is using Dispatcher.BeginInvoke. If you change your code to look like this, it should work:

if (this.Visibility == Visibility.Hidden)
{
    this.Visibility = Visibility.Visible;
    Application.Current.Dispatcher.BeginInvoke(DispatcherPriority.Background,
        new Action(delegate()
        {
            this.WindowState = WindowState.Normal;
            this.Activate();
        })
    );
}

I tried this out and it fixed the problem for me. Also, I think you can leave out the this.Activate() as well.

Answer 2

I found a better way. As the problem happens when changing the visibility of the window and the window state what I do is changing the property ShowInTaskBar instead of Visibility. Anyway a minimized window with ShowInTaskBar = true is like a hidden window.

Answer 3

From the user perspective Click the minimized icon This should then show a list of all instances of the application. right click a member of this list select maximize. Note right clicking the minimized icon will bring up a menu with the close option. To get the Maximise option you need to right click the list that appears when you click the icon.