Parsing float stored as string should throw Exception

Question

I have a string which stores a number. Now i want to parse that string and get as float.

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name          


        

Answer 1

As you can see in the related source code, the value will be trimmed:

static FloatingDecimal.ASCIIToBinaryConverter readJavaFormatString(String arg) throws NumberFormatException {
    boolean arg0 = false;
    boolean arg1 = false;

    try {
        arg = arg.trim();
     ....

So the blanks will be removed before converting to a floatValue. For more informations see the sourcecode of FloatingDecimal which is called by Float.class.

Integer.parseInt() do not trimm the string value:

public static int parseInt(String arg, int arg0) throws NumberFormatException {
    if (arg == null) {
        throw new NumberFormatException("null");
    } else if (arg0 < 2) {
        throw new NumberFormatException("radix " + arg0 + " less than Character.MIN_RADIX");
    } else if (arg0 > 36) {
        throw new NumberFormatException("radix " + arg0 + " greater than Character.MAX_RADIX");
    } else {
        int arg1 = 0;
        boolean arg2 = false;
        int arg3 = 0;
        int arg4 = arg.length();
        int arg5 = -2147483647;
        if (arg4 > 0) {
            char arg8 = arg.charAt(0);
            if (arg8 < 48) {
                if (arg8 == 45) {
                    arg2 = true;
                    arg5 = MIN_VALUE;
                } else if (arg8 != 43) {
                    throw NumberFormatException.forInputString(arg);
                }

                if (arg4 == 1) {
                    throw NumberFormatException.forInputString(arg);
                }

                ++arg3;
            }

            int arg7;
            for (int arg6 = arg5 / arg0; arg3 < arg4; arg1 -= arg7) {
                arg7 = Character.digit(arg.charAt(arg3++), arg0);
                if (arg7 < 0) {
                    throw NumberFormatException.forInputString(arg);
                }

                if (arg1 < arg6) {
                    throw NumberFormatException.forInputString(arg);
                }

                arg1 *= arg0;
                if (arg1 < arg5 + arg7) {
                    throw NumberFormatException.forInputString(arg);
                }
            }

            return arg2 ? arg1 : -arg1;
        } else {
            throw NumberFormatException.forInputString(arg);
        }
    }
}

Thats why you get an Exception there