Python How to pair two list by lambda and map

Question

For example, I have following two lists

listA=[\'one\', \'two\' , \'three\'] listB=[\'apple\',\'cherry\',\'watermelon\']

How can I pair those two lists to

Answer 1

The easiest solution would be to simply use zip as in:

>>> listA=['one', 'two' , 'three']
>>> listB=['apple','cherry','watermelon']
>>> list(zip(listA, listB))
[('one', 'apple'), ('two', 'cherry'), ('three', 'watermelon')]

I guess it would be possible to use map and lambdas, but that would just needlessly complicate things as this is really the ideal case for zip.

Answer 2

Here what I got based on what you need (map and lambda),

Input:

listA=['one', 'two' , 'three']
listB=['apple','cherry','watermelon']
list(map(lambda x, y: x+ ' ' +y, listA, listB))

Output:

['one apple', 'two cherry', 'three watermelon']

Answer 3

Using list comprehension and zip:

listA=['one', 'two' , 'three']

listB=['apple','cherry','watermelon']

new_list = [a+" "+b for a, b in zip(listA, listB)]

Output:

['one apple', 'two cherry', 'three watermelon']

Answer 4

specifically using map and lambda as asked...

list(map(lambda tup: ' '.join(list(tup)), zip(listA,listB)))

though I'd probably break that up to make it more readable

zipped   = zip(listA,listB)
tup2str  = lambda tup: ' '.join(list(tup))
result   = list(map(tup2str, zipped))
# ['one apple', 'two cherry', 'three watermelon']

EDITED - per comment below, listCombined = list(zip(listA,listB)) was a waste

Answer 5

You can use zip like below:

for item in zip(list_1, list_2):
    print(item)