Access list of items with list of indices

Question

Consider a large list of named items (first line) returned from a large csv file (80 MB) with possible interrupted spacing

name_line =  [\'a\',,\'b\',,\'c\'          


        

Answer 1

Try a generator expression,

data_line = (data_line[i] for i in good_cols)

Also read here about Generator Expressions vs. List Comprehension

as the top answer tells you: 'Basically, use a generator expression if all you're doing is iterating once'.

So you should benefit from this.