I am contributing Rust code to RosettaCode to both learn Rust and contribute to the Rust community at the same time. What is the best idiomatic way to pop the last n
I'd recommend using Vec::truncate:
fn main() {
let mut nums = vec![1, 2, 3, 4, 5];
let n = 2;
let final_length = nums.len().saturating_sub(n);
nums.truncate(final_length);
println!("{:?}", nums);
}
Additionally, I
N
elements in the vectorNormally when you "pop" something, you want to have those values. If you want the values in another vector, you can use Vec::split_off:
let tail = nums.split_off(final_length);
If you want access to the elements but do not want to create a whole new vector, you can use Vec::drain:
for i in nums.drain(final_length..) {
println!("{}", i)
}
You should take a look at the Vec::truncate function from the standard library, that can do this for you.
(playground)
fn main() {
let mut nums: Vec<u32> = Vec::new();
nums.push(1);
nums.push(2);
nums.push(3);
nums.push(4);
nums.push(5);
let n = 2;
let new_len = nums.len() - n;
nums.truncate(new_len);
for e in nums {
println!("{}", e)
}
}
An alternate approach would be to use Vec::drain instead. This gives you an iterator so you can actually use the elements that are removed.
fn main() {
let mut nums: Vec<u32> = Vec::new();
nums.push(1);
nums.push(2);
nums.push(3);
nums.push(4);
nums.push(5);
let n = 2;
let new_len = nums.len() - n;
for removed_element in nums.drain(new_len..) {
println!("removed: {}", removed_element);
}
for retained_element in nums {
println!("retained: {}", retained_element);
}
}
The drain method accepts a RangeArgument
in the form of <start-inclusive>..<end-exclusive>
. Both start and end may be omitted to default to the beginning/end of the vector. So above, we're really just saying start at new_len
and drain to the end.