For example I have some random string:
str = \"26723462345\"
And I want to split it in 2 parts after 6-th char. How to do this correctly?
This should do it
[str[0..5], str[6..-1]]
or
[str.slice(0..5), str.slice(6..-1)]
Really should check out http://corelib.rubyonrails.org/classes/String.html
_, part1, part2 = str.partition /.{6}/
https://ruby-doc.org/core-1.9.3/String.html#method-i-partition
Here's a reusable version for you:
str = "26723462345"
n = str.length
boundary = 6
head = str.slice(0, boundary) # => "267234"
tail = str.slice(boundary, n) # => "62345"
It also preserves the original string, which may come in handy later in the program.
Here’s on option. Be aware, however, that it will mutate your original string:
part1, part2 = str.slice!(0...6), str
p part1 # => "267234"
p part2 # => "62345"
p str # => "62345"
In the years since I wrote this answer I’ve come to agree with the commenters complaining that it might be excessively clever. Below are a few other options that don’t mutate the original string.
Caveat: This one will only work with ASCII characters.
str.unpack("a6a*")
# => ["267234", "62345"]
The next one uses the magic variable $'
, which returns the part of the string after the most recent Regexp match:
part1, part2 = str[/.{6}/], $'
p [part1, part2]
# => ["267234", "62345"]
And this last one uses a lookbehind to split the string in the right place without returning any extra parts:
p str.split(/(?<=^.{6})/)
# => ["267234", "62345"]
As a fun answer, how about:
str.split(/(^.{1,6})/)[1..-1]
This works because split returns the capture group matches, in addition to the parts of the string before and after the regular expression.
The best way IMO is string.scan(/.{6}/)
irb(main)> str
=> "abcdefghijklmnopqrstuvwxyz"
irb(main)> str.scan(/.{13}/)
=> ["abcdefghijklm", "nopqrstuvwxyz"]