Javascript comma list but has an and at the last one

Question

I am trying to create a function that will take a list of words -- and covert it into a sentence like this.

jsfiddle

http://jsfiddle.net/0ht35rpb/107/

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Answer 1

This should work.

function createSentence(array) {
  if (array.length == 1) {
    return array[0];
  } else if (array.length == 0) {
    return "";
  }
  var leftSide = array.slice(0, array.length - 1).join(", ");
  return leftSide + " and " + array[array.length - 1];
}

console.log(createSentence(["dogs", "cats", "fish"]));
console.log(createSentence(["dogs", "cats"]));
console.log(createSentence(["dogs"]));
console.log(createSentence([]));

Answer 2

One way is to pop off the last item, and then join and place the last item within the sting

function grammarCheck(vals) {
      //x,y,z and d
      //z
      var count = vals.length;

      var last = vals.pop()
      
      var text = vals.join(', ') + (vals.length > 1 ? ' and ' : '') + last

      return text
    }
    
    
    var arr = [
          ["emotional distress"],
          ["abc", "123", "blah", "blah", "blah"]
    ]
    
    arr.forEach(a => console.log('grammar check', grammarCheck(a)))

Answer 3

The function you have commented out seems to be right, except that it's using some property off this rather than the parameter passed to it.

Adjusting that, you get this:

const grammarCheck = function(vals) {
  return [ vals.slice(0, -1).join(", "), vals.slice(-1)[0] ]
         .join(vals.length < 2 ? "" : " and ");
}
grammarCheck(['foo']); //=> 'foo'
grammarCheck(['foo', 'bar']); //=> 'foo and bar'
grammarCheck(['foo', 'bar', 'baz']); //=> 'foo, bar and baz'
grammarCheck(['foo', 'bar', 'baz', 'qux']); //=> 'foo, bar, baz and qux'

Obviously, you could alter this a bit if you want the Oxford comma.