Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, string given [closed]

Answer 1

You have:

 mysqli_fetch_array($query)

Should be:

mysqli_fetch_array($result) 

Also in line 3 you have:

if($query === FALSE) { die(mysql_error()); } 

Should be rather:

if ($result === FALSE) { die(mysql_error()); }