“Cannot assign to” error iterating through array of struct

前端 未结 3 1169
忘掉有多难
忘掉有多难 2021-01-17 08:01

I have an array of structs:

struct CalendarDate {
    var date: NSDate?
    var selected = false
}

private var collectionData = [CalendarDate]()


        
相关标签:
3条回答
  • 2021-01-17 08:41

    As I understand it, the iterator

    for c in collectionData

    returns copies of the items in collectionData - (structs are value types, not reference types, see http://www.objc.io/issue-16/swift-classes-vs-structs.html), whereas the iteration

    for i in 0..<collectionData.count

    accesses the actual values. If I am right in that, it is pointless to assign to the c returned from the iterator... it does not "point" at the original value, whereas the

    collectionData[i].selected = false

    in the iteration is the original value.

    Some of the other commentators suggested

    for (var c) in collectionData

    but although this allows you to assign to c, it is still a copy, not a pointer to the original, and though you can modify c, collectionData remains untouched.

    The answer is either A) use the iteration as you originally noted or B) change the data type to a class, rather than a struct.

    0 讨论(0)
  • 2021-01-17 08:41

    because each 'c' is by default let, and this is a new instance of CalendarDate and the value of array at index copied to this for each step of for, and 'c' isn't pointer to the index of the array and it is just a copy of index, so if you set a new value to this, the new value does not apply in array. but 'i' is used as index of array and can directly manipulate the values of array.

    0 讨论(0)
  • 2021-01-17 08:42

    If you are using structs they are copies in the array. So even changing them only changes the copy, not an actual object in the array.

    You have to make them a variable in the loop to be editable copy, and reassign them into the array right back.

    If they are classes and not structs, than you don't have to reassign part, just do the var thing.

    for (index, var c) in collectionData.enumerated() {
            c.selected = false
            collectionData[index] = c
        }
    
    0 讨论(0)
提交回复
热议问题