How Can I Force Execution to the Catch Block?

Question

I am wondering can try..catch force execution to go into the catch and run code in there?

here example code:

try {
    if (         


        

Answer 1

public class CustomException: Exception
{
     public CustomException(string message)
        : base(message) { }

}

//

if(something == anything)
{
   throw new CustomException(" custom text message");
}

you can try this

Answer 2

You could throw an exception to force a catch

throw new Exception(...);

Answer 3

As cadrel said, but pass through an Exception to provide more feedback, which will be shown in the innerException:

try
{
    if (AnyConditionTrue)
    {
        MethodWhenTrue();
    }
    else
    {
        HandleError(new Exception("AnyCondition is not true"));
    }
}
catch (Exception ex)
{
    HandleError(ex);
}

...

private void HandleError(Exception ex) {
    throw new ApplicationException("Failure!", ex);
}

Answer 4

I think what you want is a finally block: http://msdn.microsoft.com/en-us/library/zwc8s4fz(v=vs.80).aspx

see this

try
 {
     doSomething();
 }
catch
 {
     catchSomething();
     throw an error
 } 
finally
 {
     alwaysDoThis();
 }

This is different if/when you do this:

try
 {
     doSomething(); 
 }
 catch
 {
     catchSomething(); 
     throw an error
 }
  alwaysDoThis();// will not run on error (in the catch) condition

the the this last instance, if an error occurs, the catch will execute but NOT the alwaysDoThis();. Of course you can still have multiple catch as always.

Answer 5

if(conditiontrue)
{

}
else{
    throw new Exception();
}

Answer 6

Yes, if you throw the exception that you intend to catch from within the try, it will be caught in the catch section.

I have to ask you why you would want to do this though? Exception handling is not meant to be a substitute for control flow.