The Next Palindrome number

Question

I am beginner in programming, So can you please tell me what\'s wrong with my code?

I want to print next palindrome number if the number entered by the user (n) is n

Answer 1

I have written this for finding next pallindrome number given a pallindrome number.

def palindrome(num):
    bol=False
    #x=len(str(num))
    num=num+1
    while(bol==False):
        if(check_palindrome(num)):
            bol=True
        else:
            num=num+1
    return num
def check_palindrome(n):
    temp=n
    rev=0
    while(n>0):
        dig=n%10
        rev=rev*10+dig
        n=n//10
    if(temp==rev):
        return True

b=palindrome(8)
print(b)

Answer 2

This problem has a wonderful number of ways to solve them.

One of them is

def nearest_palindrome(number):
    #start writitng your code here
    while True:
        number+=1
        if str(number) == str(number)[::-1]:
            return number 

number=12300
print(nearest_palindrome(number))

Thanks for your time to read my answer : )

Answer 3

If a definite range is given:

# function to check if the number is  a palindrome
def palin(x):                 
    s=str(x)
    if s==s[::-1]:
        return True
    else:
        return False

n=int(input("Enter the number"))
# Putting up range from the next number till 15 digits
for i in range(n+1,int(10e14)):
    if palin(i) is True:
        print(i)
        break

Answer 4

using function to find next palindrome

def nearest_palindrome(number):
if number>0:
    i=1
    while(number):
        n=number+i
        temp=n
        sum=0
        while n>0:
            rem=n%10
            sum=sum*10+rem
            n=n//10
        if temp==sum:

            return temp
            #break
        else:
            sum=0
            i=i+1
        #continue
number=12300
print(nearest_palindrome(number))

Answer 5

def nearest_palindrome(number):

    for i in range(1,number):
        number=number+1
        tem=str(number)
        tem1=tem[-1::-1]
        if(tem==tem1):
            return number
        else:
            continue

number=12997979797979797

print(nearest_palindrome(number))