Finding The Largest Number in a Nested List in Python

Question

I would like to put the max number(s) to a new array, I\'ve tried every thing that I can think of and none seem to work....(adding to an empty result array, concat, etc)

Answer 1

Wow, folks are harsh today. I think that I understood your question;

new_list = [max(i) for i in list]
for k in new_list:
     print (k)

Answer 2

Working Example in Python 2 — Tested with Python 2.6.9 and 2.7.10

L01 = [[21, 34, 345, 2], [555, 22, 6, 7], [94, 777, 65, 1], [23, 54, 12, 666]]
L02 = map(max, L01)
print(L02)

Output

[345, 555, 777, 666]

Working Example in Python 3 — Tested with Python 3.2.5 and 3.4.3 and 3.5.0

The only difference is that map() is wrapped by list().

L01 = [[21, 34, 345, 2], [555, 22, 6, 7], [94, 777, 65, 1], [23, 54, 12, 666]]
L02 = list(map(max, L01))
print(L02)

Output

[345, 555, 777, 666]

Answer 3

Just apply max to every sublist:

Python 2:   map(max, lists)
Python 3:   list(map(max, lists))

Of course the latter only works if you don't shadow the built-in list function with your variable (which is a bad idea anyway, so I used the name lists instead).

>>> lists = [[21, 34, 345, 2], [555, 22, 6, 7], [94, 777, 65, 1], [23, 54, 12, 666]]
>>> map(max, lists)
[345, 555, 777, 666]

Answer 4

newArray = [max(i) for i in list]

search up List Comprehension, one of the most useful things about python.

Answer 5

Try a list comprehension:

L = [[21, 34, 345, 2], [555, 22, 6, 7], [94, 777, 65, 1], [23, 54, 12, 666]]
maxes = [max(sublist) for sublist in L]
print(maxes)
# [345, 555, 777, 666]