if x=10 y=10 z=5 how is x<y<z=true? [duplicate]

Answer 1

It first evaluates x < y which is false (0), then 0 < z which is true (1).

Answer 2

The expression x

(x < y) < z

so it becomes

(10 < 10) < 5

which further is evaluated into

0 < 5 

which is true.

I think you wanted something like this:

x < y && y < z

Answer 3

WHat C compiler does is, in x<y<z; starts from left, so as x is not less than y therefore it replaces that expression with '0' so it becomes 0<z and as that is true. it set the variable to 1.

Answer 4

Because of operator precedence and associativity

i = x < y < z;

is parsed as:

i = ((x < y) < z);

After substituting the variable values, this becomes:

i = ((10 < 10) < 5);

Since 10 < 10 is false, this becomes:

i = (0 < 5);

Since 0 < 5 is true, that becomes:

i = 1;

Answer 5

x<y<z is not a single valid expression. Instead it evaluates x<y first (operator precedence is done left to right here) as true/false (false in this case as they're equal), converts it to an int value of 0, and then compares this value with z.

Use (x < y && y < z) instead.