JMeter: How to use Regular Expression to extract the value of a duplicate field?

Question

I have the following Response Body JSON:

{
    \"address\": [
    {
        \"id\": \"1234\"
    }
    ],
    \"id\": \"d1a4f010-48d9-434b-9b3a-2d2b12f5e38c\         


        

Answer 1

I don't know jmeter but to get the value of second id this expression

 "id"\s*:.+?"id"\s*:\s*"([^"]*)" 

It will return what you want on the $1 variable in a some languages. I suppose in jmeter you can have something similar to this in order to get the first group.

Maybe ${MYREF_g1} according this page ?

Answer 2

try with below expression

"id": "([0-9a-z-])*+"

Answer 3

Using JMeter, you can use Regular Expression Extractor ...

Reference Name: myid
Regular Expression: "id": "(.+?)"
Template: $1$
Match No.: 2

If you specify using a Match No:...

0 = Random Match
1 = First Match 
2 = Second Match
etc....

Or use corresponding variable to access the match. ${myid_2}

The variables are set as follows:

myid_matchNr - Number of matches found, possibly 0
myid_n       - (n = 1, 2, etc..) Generated by the template
myid_n_gm    - (m = 0, 1, 2) Groups for the match (n) 
myid         - By itself it is always set to the default value
myid_gn      - Not set at all

Or judging by this case, if you prefer just regex and your strings are exactly as stated. You could do..

],\s+"id": "(.+?)"

Answer 4

I tried with this:

"id":\s*"([0-9a-f\-]*)"

Answer 5

The given response values

{
    "address": [
    {
        "id": "1234"
    }
    ],
    "id": "d1a4f010-48d9-434b-9b3a-2d2b12f5e38c"
}

Regular Expression to extract the second id values

Regular Expression formats

],\s\s\s\s\s"id": "(.+)"

Note

The above regex extract the following id values
d1a4f010-48d9-434b-9b3a-2d2b12f5e38c

Answer 6

You can use a lazy regex to find the guid directly instead of finding "id"

Something like this: ([0-9a-z-]{36}).*?

If you are not sure how to create the regex, just use an online regex maker.