This is a situation I have found myself in a few times and I just want clear it up once and for all.
Best just to show you what I need to do in some example code.
You should do a join in your model for both tables, and create one result which you will move later to your view trough the controller.
Remember not to put queries in your controller.
maybe somthing like this:
function get_data($cue_sheets){
$this->db->select(clips.*);
$this->db->from('clips');
$this->db->join('cue_sheets', 'clips.idcuesheet = cue_sheets.idcuesheet' );
$this->db->where('cue_sheets.idcuesheet', $cue_sheets);
$query = $this->db->get();
}
Or something similar.
Then you bring it to the controller
$data['clips'] = $this->clips->get_data($cue_sheets);
and finally to your view
foreach($clips as $clip){
echo $clip->clip_name;
}
Hope it helps
I'm not fully certain I understand you, but I think you want to get all "clips" from all "sheets" given by the first db call. Perhaps following might work:
$this->db->from('clips');
$this->db->where_in('sheet_id', array_map( function($sheet) { return $sheet['id'] }, $data['get_cue_sheets']->result_array() ) );
$data['get_clips'] = $this->db->get();
A user on the Code Igniter Forums came up with the solution below. The original thread is here.
It’s not efficient to look up the clips for every sheet separately. Use a JOIN query to get both lists at the same time.
// get the data
$this->db->from('cue_sheets');
$this->db->where('cue_sheets.id', $id);
$this->db->join('clips', 'clips.sheet_id = cue_sheets.id', 'left');
$rawdata = $this->db->get()->result_array();
// prepare the data into a multidimensional array
$data = array();
foreach($rawdata as $row)
{
// if this is the first clip of a new sheet, make a new entry for it
if (!isset($data[$row['id']]))
{
$data[$row['id']] = $row;
$data[$row['id']]['clips'] = array();
}
// add the current clip to the sheet
$data[$row['id']]['clips'][] = $row;
}
Now in your view you can loop through the sheets, and within that, loop through the clips:
foreach($data as $sheet) {
// make header etc.
if (sizeof($sheet['clips']))
{
foreach($sheet['clips'] as $clip)
{
// show clip
}
} else {
// show 'no clips'
}
}
Thanks again,
Tim
As far as I know, there's not really a way to pass data back to the controller from the view. I myself have not ever felt the need to. Your controller should be gathering the data and then passing it to the view. If you have additional data to get from your database results, do that first and then pass it to your view along with the original data.
Maybe I'm not understanding your question though...