regular expression pattern to accept one or multiple ip addresses?

Question

I am using below regular expression pattern

pattern=\"^(\\d|[1-9]\\d|1\\d\\d|2([0-4]\\d|5[0-5]))\\.(\\d|[1-9]\\d|1\\d\\d|2([0-4]\\d|5[0-5]))\\.(\\d|[1-9]\\d         


        

Answer 1

It slowly becomes incomprehensible, but here you are:

^(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5]))(,(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])))*$

What happens here is:

let's call your IP regexp IP:

IP = ((\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])))

so we just have to repeat it with comma:

^IP(,IP)*$

Answer 2

<input type="text" name="country_code" pattern="^(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5]))(,(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])).(\d|[1-9]\d|1\d\d|2([0-4]\d|5[0-5])))*$">

Use this input field in your HTML file

Answer 3

([1-9]\d?\d?(\.\d{1,3}){2}\.\d{1,3},?)+

A little over Reductionist perhaps, but that should handle it. (you will need to trim out the commas from the matches though) Edited to restrict matches to the range of 1...* -> 999...*

Answer 4

I´d rather not use regex as @biziclop did say.

You could just split the whole String and pass the ip adress to the InetAddress.html#getByName method. from the documentation of the method:

If a literal IP address is supplied, only the validity of the address format is checked

Basicly you could just pass the adress to this method, and the class itself would supply a validation of the adress. If the addres would be invalid you would run into a java.net.UnknownHostException which you would just have to catch. This way you would just have to create a regex that will successfully split all the ip-adresses

public static void main(String[] args) throws UnknownHostException {
    String adresses = "1.1.2.3.15,192.122.134.1,198.23.45.56";
    for(String s : adresses.split(",|\\sor\\s")) {
        try {
            InetAddress adress = Inet4Address.getByName(s);
        } catch (UnknownHostException e) {
            System.out.println("Invalid format for ip adress " + s);
        }
    }
    adresses = "1.1.2.3 or 192.122.134.1 or 198.23.45.56 ";
    for(String s : adresses.split(",|\\sor\\s")) {
        try {
            InetAddress adress = Inet4Address.getByName(s);
        } catch (UnknownHostException e) {
            System.out.println("Invalid format for ip adress " + s);
        }
    }
}

output:

Invalid format for ip adress 1.1.2.3.15

Answer 5

this should work

^((2([0-4]\d|5[0-5])|1\d\d|[0]?[1-9]\d|[0]?[0]?\d)(\.(2([0-4]\d|5[0-5])|1\d\d|
[0]?[1-9]\d|[0]?[0]?\d)){3}([\s,](?!$)|$))*$

it will accept comma separated and space separated ips