html drill down drop down selected value does not inserted in MYSQL

Question

i have two drop downs. first drop down populate from database. second drop down populated from database based on selected value of first drop down.

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Answer 1

You need to concantenate them properly and also you don't you put , after last column in the query

Change following

$sql1="INSERT INTO table1 (Country, State)
VALUES ('$c', '$s',)";

to

$sql1="INSERT INTO table1 (country, state)
VALUES ('".$c."', '".$s."')";

Answer 2

if want to add options to the second drop down you need to use append not html and your using same ID i.e. #c to write the response in ajax success, change it to second drop down ID i.e. #s

you can try this:

$(document).ready(function() {
  $("#c").change(function() {
    var c1 = $('#c :selected').text();
    if(c1 != "") {
      $.ajax({
        url:'getstatw.php',
        data:{c:c1},
        type:'POST',
        success:function(response) {
          var resp = $.trim(response);
          $("#s").append(resp);
        }
      });
    } else {
      $("#c").append("<option selected value=''>Select state</option>");
    }
  });
});

then remove , in insert query.

$sql1="INSERT INTO table1 (Country, State)
VALUES ('$c', '$s')";