Getting error in PHP 5.3 which works in php 5.4 [closed]

Answer 1

Yes, is realated to php version.

This is because php 5.3 interpreter, doesn't accept a sytnax like $user->getGeoCode()['latitude']

while php 5.4 interpreter does.

Answer 2

As PHP documentation says:

PHP 5.4.0 offers a wide range of new features:

• Support for traits has been added.
  
• Short array syntax has been added, e.g. $a = [1, 2, 3, 4]; or $a = ['one' => 1, 'two' => 2, 'three' => 3, 'four' => 4];.
  
• Function array dereferencing has been added, e.g. foo()[0].
  
• Closures now support $this.
  
• < ?= is now always available, regardless of the short_open_tag php.ini option.
  
• Class member access on instantiation has been added, e.g. (new Foo)->bar().
  
• Class::{expr}() syntax is now supported.
  
• Binary number format has been added, e.g. 0b001001101.
  
• Improved parse error messages and improved incompatible arguments warnings.
  
• The session extension can now track the upload progress of files.
  
• Built-in development web server in CLI mode.
  

Try this:

if ($geodata = $user->getGeoCode()) { 
    $latitude = $geodata['latitude'];
}

Answer 3

Error message explains everything. PHP5.3 doesn't support casting function output automatically to array and accessing it like this.

Since PHP 5.4 it's possible to do exactly that Example

Prior to PHP 5.3, you'll need to use a temporary variable.

EDIT

by casting I ment dereferencing.

Answer 4

In the PHP documentation you can find the explanation:

As of PHP 5.4 it is possible to array dereference the result of a function or method call directly. Before it was only possible using a temporary variable.

Answer 5

Yes, because this is new feature of PHP 5.4.short hand array is not supported by 5.3