Remove all items in Python list containing a number [duplicate]

Answer 1

>>> foo = ['This', 'That', 'Those4423', '42', '13b', 'Yes', '2']
>>> foo1 = [x for x in foo if not any(x1.isdigit() for x1 in x)]
>>> foo
['This', 'That', 'Those4423', '42', '13b', 'Yes', '2']
>>> foo1
['This', 'That', 'Yes']
>>>

However you can use .isalpha() to check if the string contains alphabetic characters only.

.isaplha()
 [x for x in foo if x.isalpha()]

Answer 2

Using a list comprehension:

[element for element in my_list if all(digit not in element for digit in "1234567890")]