I managed to create a list of prime numbers in a given range using this:
import numpy as np
num = int(input(\"Enter a number: \"))
for a in range(2,num
In your case, a
is an integer variable being used in your loop, not an iterable.
import numpy as np
num = int(input("Enter a number: "))
primes = []
for a in range(2,num+1):
maxInt= int(np.sqrt(a)) + 1
for i in range(2,maxInt):
if (a%i==0):
break
else:
primes.append(a)
print(sum(primes))
So if we just append them to a list as we go instead of printing them, we get the following output when taking the sum
of the list primes
.
Enter a number: 43
281
Sum them inside the loop
import numpy as np
num = int(input("Enter a number: "))
result=0
for a in range(2,num+1):
maxInt=int(np.sqrt(a)) + 1
for i in range(2,maxInt):
if (a%i==0):
break
else:
print (a)
result+=a
print(result)
If you want to use sum, you could make a generator function, yielding each a
in the loop so you have an iterable to call sum on:
num = int(input("Enter a number: "))
def sum_range(num):
for a in range(2, num + 1):
maxInt = int(a **.5) + 1
for i in range(2, maxInt):
if a % i == 0:
break
else:
yield a
print(sum(sum_range(num)))