Finding a list in a list of lists with the max value by given index and returning its first value

Question

I have a list of lists and I want to find the max value by one index in the lists, in this case [5].

Once I have the max value, how would I find where that occurs and

Answer 1

This is what you can do, using list comprehension twice

inputlist = [[70, 'Cherry St,', 43.684371, -79.316756, 23, 9, 14, True, True],
[78, 'Cow Rd', 43.683378, -79.322961, 15, 13, 2, True, False]]

The max value at the 5th index , considering all the list in inputlist. You can use this for any(n) no of member list.

value_5th = max([listt[5] for listt in inputlist])

Once you reach at that:

This will give you the first element of that member list which has that largest/max element at the 5th index amongst all other member list.Plz note that this will work even if multiple member lists have same max element at their 5th index

Your_ans = [ listt[0] for listt in inputlist if value_5th in listt]

Just trying to give you a more robust solution.Although ans given above is quite clever in my view.

Answer 2

Use the max() function, but pass through an argument to check a specific index:

max(inputList, key=lambda x: x[5])

This returns the sublist in inputList that has the greatest value at index 5. If you want to actually access this value, add [5] to the end of the statement.

Since it seems that you want the ID of the list with the maximum 5th element, add [0] to the end:

max(inputList, key=lambda x: x[5])[0]