Python timer countdown

Question

I want to know about timer in Python.

Suppose i have a code snippet something like:

def abc()
   print \'Hi\'  
   print \'Hello\'
   print \'Hai\'
<         


        

Answer 1

Use time.sleep.

import time

def abc():
    print 'Hi'
    print 'Hello'
    print 'Hai'

for i in xrange(3):
    time.sleep(1)
    abc()   

Answer 2

import time
def abc():
 print 'Hi'
 print 'Hello'
 print 'Hai'

for i in range(3):
 time.sleep(3-i)
 abc()

Answer 3

import time
def abc()
    for i in range(3):
        print 'Hi'  
        print 'Hello'
        print 'Hai'
        time.sleep(1)

Answer 4

import sys
import time

c=':'
sec = 0
min = 0
hour = 0

#count up clock

while True:
for y in range(59):                                                 #hours
    for x in range (59):                                            #min
        sec = sec+1
        sec1 = ('%02.f' % sec)                                      #format
        min1 = ('%02.f' % min)
        hour1= ('%02.f' % hour)
        sys.stdout.write('\r'+str(hour1)+c+str(min1)+c+str(sec1))   #clear and write
        time.sleep(1)
    sec = 0
    sys.stdout.write('\r' + str(hour1) + c + str(min1) + c + '00')  #ensure proper timing and display
    time.sleep(1)
    min=min+1
min = 0
sys.stdout.write('\r' + str(hour1) + c + str(min1) + c + '00')      #ensure proper timing and display
time.sleep(1)
hour=hour+1

Answer 5

time.sleep is fine in this case but what if the abc() function takes half a second to execute? Or 5 minutes? In this case you should use a Timer object.

from threading import Timer

def abc():
    print 'Hi'  
    print 'Hello'
    print 'Hai'

for i in xrange(3):
    Timer(i, abc).start()

Answer 6

usually for me this works...

import time

def abc():
    print 'Hi'
    time.sleep(1)
    print 'Hello'
    time.sleep(1)
    print 'Hai'
    time.sleep(1)

I think you can guess after that...