“Can only iterable” Python error

前端 未结 3 1918
面向向阳花
面向向阳花 2021-01-16 12:34

Hello my fellow programmers.

I am a fairly new programmer, and now I am facing a great predicament. I am getting the error:

can only assign an iterab         


        
相关标签:
3条回答
  • 2021-01-16 13:09

    An iterable is a thing with multiple items that you can iterate through (for example: take the 1st value do something, then the 2nd do something, etc...) Lists, dictionaries, tuples, strings have several items in them and can be used as iterables. As a counterexample: number types don't qualify as iterable.

    Remember that computers count from #0 so: if you want the first value of a list you can use

    my_list[0]
    

    before you go further I would suggest watching this video about looping. https://www.youtube.com/watch?v=EnSu9hHGq5o

    0 讨论(0)
  • 2021-01-16 13:16

    The RHS of a slice-assignment must be an iterable, not a scalar. Consider slice-deleting and then appending instead.

    0 讨论(0)
  • 2021-01-16 13:26

    int_lis[:] = duplic_int_lis [int_firs] means assign all the items of duplic_int_lis [int_firs] to int_lis, so it expects you to pass an iterable/iterator on the RHS.

    But in your case you're passing it an non-iterable, which is incorrect:

    >>> lis = range(10)
    >>> lis[:] = range(5) 
    >>> lis               #all items of `lis` replaced with range(5)
    [0, 1, 2, 3, 4]
    
    >>> lis[:] = 5        #Non-iterable will raise an error.
    Traceback (most recent call last):
      File "<ipython-input-77-0704f8a4410d>", line 1, in <module>
        lis[:] = 5
    TypeError: can only assign an iterable
    
    >>> lis[:] = 'foobar' #works for any iterable/iterator
    >>> lis
    ['f', 'o', 'o', 'b', 'a', 'r']
    

    As you cannot iterate over an integer, hence the error.

    >>> for x in 1: pass
    Traceback (most recent call last):
      File "<ipython-input-84-416802313c58>", line 1, in <module>
        for x in 1:pass
    TypeError: 'int' object is not iterable
    
    0 讨论(0)
提交回复
热议问题