How to print an entered string backwards in C using only a for loop

Question

I want to print a string backwards. But my code seems to count down the alphabet from the last letter in the array to the first letter in the array instead of counting down

Answer 1

#include <stdio.h>
#include <stdlib.h>

/*
 * 
 */
int main(int argc, char** argv) {
    int i;
    char letters[3]="";
    printf("Enter three letters!");
    scanf("%s",letters);
    for(i=3;i>=0;i--){
        printf("%c", letters[i]);
    }
    return (EXIT_SUCCESS);
}

Answer 2

You want to print word[x] (the xth character in the array) instead of x (the xth character in the character set).

You also want to be counting down indexes, not characters.

for(x=end, x >= 0; x--)
    printf("%c", word[x]);

Answer 3

//Change end to int type and modify your for loop as shown.
#include <stdio.h>
#include <string.h>

int main(void) 
{

char word[50];
int end;
char x;

printf("Enter a word and I'll give it to you backwards: ");

scanf("%s", word);

end = strlen(word) - 1;

 for (x = end; x >= 0; x--) 
 printf("%c",word[x] );


return 0;
}

Answer 4

What you have loops between the array element values. You want to loop between the array indexes. Update your loop to the following:

for (x = end; x >= 0; --x) {
    printf("%c", word[x]);
}

Note that this goes from the last index to zero and output the character at that index. Also a micro-optimization in the for loop using pre-decrement.

Answer 5

In your loop, x is the index into the character array comprising word. So x should change from end to 0, and referencing the array should be as word[x].

Answer 6

You're calling array values and not the specific index.

for(x = end; x >= 0; x--) { printf("%c", word[x]); }