2+ out of 4 conditions regex

Question

I have 4 requirements for user passwords:

• At least 1 a-z char
• At least 1 A-Z char
• At least 1 0-9 char
• At least 1 symbol in .

Answer 1

You can use following expression:

/[a-z]/.test(pass)+/[A-Z]/.test(pass)+/\d/.test(pass)+/[.!@#$%^&*()_]/.test(pass)>2

Answer 2

Always break down big problems into smaller ones.

Define a separate Regex for each of your four different conditions, then check if enough of them are fulfilled.

For example:

var checks = {
    lowercase: /[a-z]/,
    uppercase: /[A-Z]/,
    number: /[0-9]/,
    symbol: /[.!@#$%^&*()_]/
}, passcount = 0, results = {};
for( var k in checks) if( checks.hasOwnProperty(k)) {
    if( checks[k].test(password)) {
        passcount++;
        results[k] = true;
    }
    else results[k] = false;
}
if( passcount < 2) {
    alert("Your password didn't meet enough conditions.\n" +
      "[Provide useful info here - 'results' object lists " +
      "whether each test passed or failed, so use that for " +
      "a user-friendly experience!]");
    return false;
}
return true;

And finally, obligatory xkcd comic: