How can I synchronize three threads?

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北恋
北恋 2021-01-16 10:44

My app consist of the main-process and two threads, all running concurrently and making use of three fifo-queues:

The fifo-q\'s are Qmain, Q1 and Q2. Internally the

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  • 2021-01-16 11:07

    I wrote a simple application below:

    #include <queue>
    #include <windows.h>
    #include <process.h>
    using namespace std;
    
    queue<int> QMain, Q1, Q2;
    CRITICAL_SECTION csMain, cs1, cs2;
    
    unsigned  __stdcall TMaster(void*)
    {
        while(1)
        {
            if( Q1.size() > 0)
            {
                ::EnterCriticalSection(&cs1);
                ::EnterCriticalSection(&csMain);
                int i1 = Q1.front();
                Q1.pop();
                //use i1;
                i1 = 2 * i1;
                //end use;
                QMain.push(i1);
                ::LeaveCriticalSection(&csMain);
                ::LeaveCriticalSection(&cs1);
            }
            if( Q2.size() > 0)
            {
                ::EnterCriticalSection(&cs2);
                ::EnterCriticalSection(&csMain);
                int i1 = Q2.front();
                Q2.pop();
                //use i1;
                i1 = 3 * i1;
                //end use;
                QMain.push(i1);
                ::LeaveCriticalSection(&csMain);
                ::LeaveCriticalSection(&cs2);
            }
        }
        return 0;
    }
    
    unsigned  __stdcall TMoniter(void*)
    {
        while(1)
        {
            int irand = ::rand();
            if ( irand % 6 >= 3)
            {
                ::EnterCriticalSection(&cs2);
                Q2.push(irand % 6);
                ::LeaveCriticalSection(&cs2);
            }
        }
        return 0;
    }
    
    unsigned  __stdcall TMain(void)
    {
        while(1)
        {
            if (QMain.size() > 0)
            {
                ::EnterCriticalSection(&cs1);
                ::EnterCriticalSection(&csMain);
                int i = QMain.front();
                QMain.pop();
                i = 4 * i;
                Q1.push(i);
                ::LeaveCriticalSection(&csMain);
                ::LeaveCriticalSection(&cs1);
            }
        }
        return 0;
    }
    
    int _tmain(int argc, _TCHAR* argv[])
    {
        ::InitializeCriticalSection(&cs1);
        ::InitializeCriticalSection(&cs2);
        ::InitializeCriticalSection(&csMain);
        unsigned threadID;
        ::_beginthreadex(NULL, 0, &TMaster, NULL, 0, &threadID);
        ::_beginthreadex(NULL, 0, &TMoniter, NULL, 0, &threadID);
        TMain();
    
        return 0;
    }
    
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  • 2021-01-16 11:08

    1 problem may occur due to this rule "The main-process must continue running all the time, must not be blocked on a 'read'". How did you implement it? what is the difference between 'get' and 'read'?

    Problem seems to be in your implementation, not in the logic. And as you stated, you should not be in any dead lock because you are not acquiring another lock whether in a lock.

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  • 2021-01-16 11:12

    An example of how I would adapt the design and lock the queue access the posix way. Remark that I would wrap the mutex to use RAII or use boost-threading and that I would use stl::deque or stl::queue as queue, but staying as close as possible to your code:

    main-process:
    ...
    start thread Monitor
    ...
    while (!quit)
    {
        ...
        if (Qmain.count() > 0)
        {
            X = Qmain.get();
            process(X) 
                delete X;
        }
        ...
        //at some random time:
        QMain.put(Y);
        ...
    }
    
    Monitor:
    {
        while (1)
        {
            //obtain & package data
            QMain.put(data)
        }
    }
    
    fifo_q:
    template < class X* > class fifo_q
    {
        struct item
        {
            X* data;
            item *next;
            item() { data=NULL; next=NULL; }
        }
        item *head, *tail;
        int count;
        pthread_mutex_t m;
    public:
        fifo_q() { head=tail=NULL; count=0; }
        ~fifo_q() { clear(); /*deletes all items*/ }
        void put(X x) 
        { 
          pthread_mutex_lock(&m);
          item i=new item(); 
          (... adds to tail...); 
          count++; 
          pthread_mutex_unlock(&m);
        }
        X* get() 
        { 
          pthread_mutex_lock(&m);
          X *d = h.data; 
          (...deletes head ...); 
          count--; 
          pthread_mutex_unlock(&m);
          return d; 
        }
        clear() {...}
    };
    

    Remark too that the mutex still needs to be initialized as in the example here and that count() should also use the mutex

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  • 2021-01-16 11:22

    You should not lock second mutex when you already locked one.

    Since the question is tagged with C++, I suggest to implement locking inside get/add logic of the queue class (e.g. using boost locks) or write a wrapper if your queue is not a class.

    This allows you to simplify the locking logic.

    Regarding the sources you have added: queue size check and following put/get should be done in one transaction otherwise another thread can edit the queue in between

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  • 2021-01-16 11:30

    Are you acquiring multiple locks simultaneously? This is generally something you want to avoid. If you must, ensure you are always acquiring the locks in the same order in each thread (this is more restrictive to your concurrency and why you generally want to avoid it).

    Other concurrency advice: Are you acquiring the lock prior to reading the queue sizes? If you're using a mutex to protect the queues, then your queue implementation isn't concurrent and you probably need to acquire the lock before reading the queue size.

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  • 2021-01-16 11:32

    Use the debugger. When your solution with mutexes hangs look at what the threads are doing and you will get a good idea about the cause of the problem.

    What is your platform? In Unix/Linux you can use POSIX message queues (you can also use System V message queues, sockets, FIFOs, ...) so you don't need mutexes.

    Learn about condition variables. By your description it looks like your Qmaster-thread is busy looping, burning your CPU.

    One of your responses suggest you are doing something like:

    Q2_mutex.lock()
    Qmain_mutex.lock()
    Qmain.put(Q2.get())
    Qmain_mutex.unlock()
    Q2_mutex.unlock()
    

    but you probably want to do it like:

    Q2_mutex.lock()
    X = Q2.get()
    Q2_mutex.unlock()
    
    Qmain_mutex.lock()
    Qmain.put(X)
    Qmain_mutex.unlock()
    

    and as Gregory suggested above, encapsulate the logic into the get/put.

    EDIT: Now that you posted your code I wonder, is this a learning exercise? Because I see that you are coding your own FIFO queue class instead of using the C++ standard std::queue. I suppose you have tested your class really well and the problem is not there.

    Also, I don't understand why you need three different queues. It seems that the Qmain queue would be enough, and then you will not need the Qmaster thread that is indeed busy waiting.

    About the encapsulation, you can create a synch_fifo_q class that encapsulates the fifo_q class. Add a private mutex variable and then the public methods (put, get, clear, count,...) should be like put(X) { lock m_mutex; m_fifo_q.put(X); unlock m_mutex; }

    question: what would happen if you have more than one reader from the queue? Is it guaranteed that after a "count() > 0" you can do a "get()" and get an element?

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