Draw Line Using UIPinchGeustureRecognizer

Question

I want to draw line using UIPinchGeustureRecognizer,I have tried all stackoverflow solution but no luck. please help me to resolve this. I am getting following error

Answer 1

You must subclass the UIView and override the drawRect: method, the CGContextRef you get with UIGraphicsGetCurrentContext is invalid out of drawRect: method and don't establish a strong reference to the graphics context because it can change between calls to the drawRect: method.

When you recognize the pinch gesture, pass the CGPoint to the view and send setNeedsDisplay method to it.

Always use setNeedsDisplay to refresh the view, don't send drawRect: directly.

LineView.m

- (void)drawRect:(CGRect)rect
{
    // p1 and p2 should be set before call `setNeedsDisplay` method
    [self drawRect:location1 Loc2:location2] ;
}

- (void)drawRect:(CGPoint)location1 Loc2:(CGPoint)location2 {
    CGContextRef context = UIGraphicsGetCurrentContext();
    CGContextSetLineWidth(context, 5.0);
    CGColorSpaceRef colorspace = CGColorSpaceCreateDeviceRGB();
    CGFloat components[] = {0.0, 0.0, 1.0, 1.0};
    CGColorRef color = CGColorCreate(colorspace, components);
    CGContextSetStrokeColorWithColor(context, color);
    CGContextMoveToPoint(context, location1.x, location1.y);
    CGContextAddLineToPoint(context, location2.x, location2.y);
    CGContextStrokePath(context);
    CGColorSpaceRelease(colorspace);
    CGColorRelease(color);
}

Edit: I assume you only draw the line when two fingers are on.

- (void)handleLinePinch:(UIPinchGestureRecognizer *)gesture
{
    NSUInteger num_touches = [gesture numberOfTouches];

    // save locations to some instance variables, like `CGPoint location1, location2;`
    if (num_touches == 2) {
       location1 = [gesture locationOfTouch:0 inView:l];
       location2 = [gesture locationOfTouch:1 inView:l];
    }
    // you need save location1 and location2 to `l` and refresh `l`.
    // for example: l.location1 = location1; l.location2 = location2;
    [l setNeedsDisplay];

}