Groovy: Node.replaceNode with Node?

Question

Suppose I have a node I\'d like to replace with replaceNode, however, I don\'t want to use a Builder to do it - or rather, I already have the node

Answer 1

If you don't mind switching to XmlSlurper() the following should work:

def top = new XmlSlurper().parse('input.xml')
top.middle.each { node ->
    node.replaceNode {
        mkp.yield(new XmlSlurper().parse('replacement.xml')) 
    }   
}

Which will replace all middle nodes with the contents of replacement.xml