Python efficiently split currency sign and number in one string

Question

I have a string like \'$200,000,000\' or \'Yan300,000,000\'

I want to split the currency and number, and output a tuple (\'$\', \'200

Answer 1

You can use regex for this.

p1 = re.compile("\d")  #match digits
p2 = re.compile("\D")  match non-digits


currency_symbol = p1.split(cur_str)[0]
value = int("".join([group for group in p2.split(cur_str)]))

Answer 2

import locale
import re
locale.setlocale(locale.LC_ALL, 'en_US.UTF-8')

def split_currency(text):
    _, currency, num = re.split('^(\D+)', text, 1)
    num = locale.atoi(num)
    return currency, num
print(split_currency('$200,000,000'))
# ('$', 200000000)
print(split_currency('Yan300,000,000'))
# ('Yan', 300000000)

split_currency will raise a ValueError if text does not start with a currency symbol (or anything that is not a digit). You could use try...except to handle that case differently if you wish.

Answer 3

>>> import re
>>> string = 'YAN300,000,000'
>>> match = re.search(r'([\D]+)([\d,]+)', string)
>>> output = (match.group(1), match.group(2).replace(',',''))
>>> output
('YAN', '300000000')

(Thanks to zhangyangyu for pointing out I hadn't fully answered the question)

Answer 4

>>> filter(str.isdigit, s)
'200000000'
>>> filter(lambda x: not x.isdigit() and x != ',', s)
'$'
>>> 
>>> (filter(lambda x: not x.isdigit() and x != ',' ,s), filter(str.isdigit, s))
('$', '200000000')
>>> 

Answer 5

>>> import itertools
>>> myStr = '$200,000,000'
>>> ''.join(itertools.dropwhile(lambda c: not c.isdigit(), myStr))
'200,000,000'
>>> myStr = 'Yan300,000,000'
>>> ''.join(itertools.dropwhile(lambda c: not c.isdigit(), myStr))
'300,000,000'

Similarly, you could use itertools.takewhile with the same lambda function to get the currency sign. However, this might be simpler:

idx = itertools.dropwhile(lambda c: not c.isdigit()).next()
sign, val = myStr[:idx], myStr[idx:]

Answer 6

It wont be faster I bet ... but I think its more readable

>>> cur_string = "asd1,23456,123,1233"
>>> cur_sym = re.search(r"([^0-9, ]*)[0-9]","asd123").groups()[0]
>>> cur = re.sub("[^0-9]","",cur_string)
>>> print cur_sym,int(cur)
asd 1234561231233