Regular expression to match phone numbers with country codes

Question

This is the regular expression I use to match phone numbers like:

00 00 00 00 00
00 00 0 00 00 00 00
+00 0 00 00 00 00

(\\d{2}\\s+\\d{2}\\s+\\d{2}\\s+\\d{2}         


        

Answer 1

1. Where you have your alternative formats listed like:

   (...)\s+(...)\s+(...)
   

   Change that to use the | (OR) operator:

   (...)|(...)|(...)
   

2. Don't escape the parentheses. \( and \) should be simply ( and ).

3. In your third group the + at the beginning should be escaped with a backslash:

   (\+\d{2}\s+\d\s+\d{2}\s+\d{2}\s+\d{2}\s+\d{2})
   

Answer 2

Escaping the parenthesis turns them into literals. Try it without the escapes:

/^(\d{2}\s+\d{2}\s+\d{2}\s+\d{2}\s+\d{2})\s+(\d{2}\s+\d{2}\s+\d\s+\d{2}\s+\d{2}\s+\d{2}\s+\d{2})\s+(\d{2}\s+\d\s+\d{2}\s+\d{2}\s+\d{2}\s+\d{2})/

Answer 3

Try this instead:

\d\d(\s+\d\d){4}|(\d\d\s+\d\d\s+\d|\+\s+\d)\d\d(\s+\d\d){3}

which means:

\d\d(\s+\d\d){4}    // 00 00 00 00 00

|                   // OR

(                   // (
  \d\d\s+\d\d\s+\d  //    00 00 0
  |                 //    OR
  \+\s+\d           //    + 0
)                   // )
\d\d(\s+\d\d){3}    // 00 00 00 00

Answer 4

In the javascript, you have escaped all the brackets. Do you want them to behave as capturing groups, or do you want to match actual brackets in the string?

Also use test instead of search. test returns true or false, not a number.

Answer 5

Try this:

var re = /^\+?(\d{1,2} ?)+$/g
var phone = "00 00 00 00 00"; //"00 00 00 00 00x"; 
if(!re.test(phone))
    alert("wrong phone pattern");