Passing function argument to formula

Question

I\'m trying to understand why

foo = function(d,y,x) {
    fit = with(d, lm(y ~ x))
}
foo(myData, Y, X)

won\'t work, where for instance

Answer 1

@DMT's answer explains what's going on nicely.

Here are the hoops to jump through if you want things to work as you expect:

lmwrap <- function(d,y,x) {
    ys <- deparse(substitute(y))
    xs <- deparse(substitute(x))
    f <- reformulate(xs,response=ys)
    return(lm(f,data=d))
}
mydata <- data.frame(X=1:10,Y=rnorm(10))
lmwrap(mydata,Y, X)

Or it can be simplified a bit if you pass the column names as strings rather than symbols.

lmwrap <- function(d,y,x) {
    f <- reformulate(xs, response=ys)
    return(lm(f, data=d))
}
lmwrap(mydata, "Y", "X")

This approach will be a bit fragile, e.g. if you pass arguments through another function. Also, getting the "Call" part of the formula to read Y~X takes more trickery ...

Answer 2

Y and X are your column names, not variables. They wouldn't in this case, be arguments to your function unless you passed them in as strings and essentially call

lm(mydata[,"Y"]~ mydata[,"X"])

If you were to run ls() on your console, Y and X would most likely not be there, so the function won't work. Print both x and y prior to the fit = call, and you'll likely see NULLs, which won't fly in lm.

One way to do this in your form is the following

lmwrap<-function(df, yname, xname){
fit=lm(d[,yname] ~ d[,xname])
}

lmwrap(mydata,"Y", "X")

But you could just make the lm call like regular