Sum of same object name in javascript

Question

Hi friends I\'m beginner for javascript how i sum same n no\'s of object name corresponding value and push the result to new array.see this is sample object

va

Answer 1

Store these objects in an array, such as:

var myObjects = [
    {'delivered':10,'due':11,'team_name':'UK'},
    {'delivered':10,'due':11,'team_name':'US'},
    {'delivered':10,'due':11,'team_name':'UK'}
];

Create a new object in which you will store your results:

var results = {};

Then iterate through the array with a for loop (as it is generally faster) and add the other properties according to team_name:

for (var i = 0; i <= myObjects.length; i++) {
    if (typeof results[myObjects[i].team_name] !== undefined) {
        results[myObjects[i]].delivered += myObjects[i].delivered;
        results[myObjects[i]].due += myObjects[i].due; 
    } else {
        // Set 0 to these properties if the entry didn't exist
        results[myObjects[i]].delivered = 0;
        results[myObjects[i]].due = 0;
    }
}

Answer 2

var obj_1 ={'delivered':10,'due':11,'team_name':'UK'};
var obj_2 ={'delivered':10,'due':11,'team_name':'US'};
var obj_nth ={'delivered':10,'due':11,'team_name':'UK'};

function sum_all() { 
    var sum={}; 
    for(var i=0;i<arguments.length;i++) { 
        obj = arguments[i]; 
        if (!sum[obj.team_name]) { 
            sum[obj.team_name]={'delivered':0,'due':0}; 
        } 
        sum[obj.team_name].delivered += obj.delivered; 
        sum[obj.team_name].due += obj.due;    
    } 
    return sum; 
}

var sum = sum_all(obj_1,obj_2,obj_nth);

console.log(sum);

Your console output will be:

sum
Object
  UK: Object
      delivered: 20
      due: 22

  US: Object
      delivered: 10
      due: 11

Answer 3

You can first create array of objects and then reduce() to return one object.

var obj_1 ={'delivered':10,'due':11,'team_name':'UK'};
var obj_2 ={'delivered':10,'due':11,'team_name':'US'};
var obj_nth ={'delivered':10,'due':11,'team_name':'UK'};

var result = [obj_1, obj_2, obj_nth].reduce(function(r, e) {
  if(!r[e.team_name]) {
    r[e.team_name] = {delivered:0,due:0}
  }
  r[e.team_name].delivered += e.delivered
  r[e.team_name].due += e.due
  return r
}, {})

console.log(result)

Answer 4

const newArray = initialArray.map(({team_name, ...restProps}) => {
  return {
    [team_name]: {...restProps}
  };
});

See:

• Arrow functions
• Spread operator
• Array.prototype.map
• Computed property names