Dict with same keys names

Question

I need a dictionary that has two keys with the same name, but different values. One way I tried to do this is by creating a class where I would put the each key name of my d

Answer 1

What you are trying to do is not possible with dictionaries. In fact, it is contrary to the whole idea behind dictionaries.

Also, your Sets class won't help you, as it effectively gives each name a new (sort of random) hash code, making it difficult to retrieve items from the dictionary, other than checking all the items, which defeats the purpose of the dict. You can not do dict.get(Sets(some_name)), as this will create a new Sets object, having a different hash code than the one already in the dictionary!

What you can do instead is:

1. Just create a list of (name, value) pairs, or

   pairs = zip(names, values) # or list(zip(...)) in Python 3
   

2. create a dictionary mapping names to lists of values.

   dictionary = {}
   for n, v in zip(names, values):
       dictionary.setdefault(n, []).append(v)
   

The first approach, using lists of tuples, will have linear lookup time (you basically have to check all the entries), but the second one, a dict mapping to lists, is as close as you can get to "multi-key-dicts" and should serve your purposes well. To access the values per key, do this:

for key, values in dictionary.iteritems():
    for value in values:
        print key, value

Answer 2

Instead of wanting multiple keys with the same name, could you getting away of having multiple values per each key?

names = [1]
values = [[1, 2, 3], [4, 5, 6]]

dict = {}

for i in names:
    dict[i] = values

for k,v in dict.items():
    for v in dict[k]:
        print("key: {} :: v: {}".format(k, v))

Output:

key: 1 :: v: [1, 2, 3]
key: 1 :: v: [4, 5, 6]

Then you would access each value like this (or in a loop):

print("Key 1 value 1: {}".format(dict[1][0]))
print("Key 1 value 2: {}".format(dict[1][1]))