How to validate list of UUID's AND return UUID Version?

Question

I\'m needing to both validate a list of UUID\'s as well as determine the version. For example, using https://www.beautifyconverter.com/uuid-validator.php and entering 25CCCA

Answer 1

Here is how I would iterative over a list of potential UUIDs and return a parallel list with either the version number (if valid) or None otherwise.

Note especially that the UUID constructor accepts UUID strings of any version. If the string is valid, you can query the .version member to determine the version.

from uuid import UUID


def version_uuid(uuid):
    try:
        return UUID(uuid).version
    except ValueError:
        return None

def version_list(l):
    return [version_uuid(uuid) for uuid in l]

if __name__=="__main__":
    uuids = (
        '0d14fbaa-8cd6-11e7-b2ed-28d244cd6e76',
        '6fa459ea-ee8a-3ca4-894e-db77e160355e',
        '16583cd3-8361-4fe6-a345-e1f546b86b74',
        '886313e1-3b8a-5372-9b90-0c9aee199e5d',
        '0d14fbaa-8cd6-11e7-b2ed-28d244cd6e7',
        '6fa459ea-ee8a-3ca4-894e-db77e160355',
        '16583cd3-8361-4fe6-a345-e1f546b86b7',
        '886313e1-3b8a-5372-9b90-0c9aee199e5',
        '481A8DE5-F0D1-E211-B425-E41F134196DA',
    )
    assert version_list(uuids) == [1,3,4,5,None,None,None,None,14]

Answer 2

def validate_uuid4(uuid_string):

    try:
        val = UUID(uuid_string, version=4)
    except ValueError:
        # If it's a value error, then the string 
        # is not a valid hex code for a UUID.
        return False

    return True

You can use the above function to go through your list of uuid string and it will tell you whether a particular string in the list if a valid version 4 uuid