Multiple files upload in selenium webdiver

Answer 1

that easy like //input[@type="file"] will point to the first input tag and (//input[@type="file"])[{INDEX}] where INDEX is the number of the of the input tag note: indexing in xpath starts from 1

OR you can use the

file_tag_list =driver.find_elements_by_xpath(//input[@type="file"])

function that the python syntax you can find it for different languages just google it. this function will return a list of webdriver element and then you can

file_tag_list[0].send_keys(filepath)
file_tag_list[1].send_keys(filepath)

Answer 2

Holy ##### it even works in PHP:

public function waitForAjax()
{
    while(true)
    {
        $ajaxIsComplete = array(
            'script' => 'return jQuery.active == 0',
            'args' => array()
        );
        $ajaxIsComplete = $this->execute($ajaxIsComplete);
        if ($ajaxIsComplete) {
            break;
        }
    }
}

Thank you :)

Answer 3

This works on Chrome:

driver.findElement(By.id("input1")).sendKeys("path/to/first/file-001 \n path/to/first/file-002 \n path/to/first/file-003");

Answer 4

You would do so the same as you would if you were only uploading one file.

driver.findElement(By.id("input1")).sendKeys("path/to/first/file");
driver.findElement(By.id("input2")).sendKeys("path/to/second/file");
driver.findElement(By.id("input3")).sendKeys("path/to/third/file");
driver.findElement(By.id("input4")).sendKeys("path/to/fourth/file");
driver.findElement(By.id("input5")).sendKeys("path/to/fifth/file");
driver.findElement(By.id("upload")).click();

Obviously, you'll need to put in your own correct IDs or whatever.